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Iris / Iris
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Robbert Krebbers authored
It used to be: (P ={E}=> Q) := (True ⊢ (P → |={E}=> Q)) Now it is: (P ={E}=> Q) := (P ⊢ |={E}=> Q)
Robbert Krebbers authoredIt used to be: (P ={E}=> Q) := (True ⊢ (P → |={E}=> Q)) Now it is: (P ={E}=> Q) := (P ⊢ |={E}=> Q)