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Commit c081e1b7 authored by Ralf Jung's avatar Ralf Jung
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more generalization of lemmas and a few comments for [solve_ndisj]

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1 merge request!75make solve_ndisj more powerful
......@@ -66,9 +66,6 @@ Section namespace.
Lemma ndot_preserve_disjoint_r N E x : E ## N E ## N.@x.
Proof. intros. by apply symmetry, ndot_preserve_disjoint_l. Qed.
Lemma ndisj_difference_l E N1 N2 : N2 (N1 : coPset) E N1 ## N2.
Proof. set_solver. Qed.
End namespace.
(* The hope is that registering these will suffice to solve most goals
......@@ -77,17 +74,25 @@ of the forms:
- [↑N1 ⊆ E ∖ ↑N2 ∖ .. ∖ ↑Nn]
- [E1 ∖ ↑N1 ⊆ E2 ∖ ↑N2 ∖ .. ∖ ↑Nn] *)
Create HintDb ndisj.
(* Rules for goals of the form [_ ⊆ _] *)
(* If-and-only-if rules. Well, not quite, but for the fragment we are
considering they are. *)
Hint Resolve (subseteq_difference_r (A:=positive) (C:=coPset)) : ndisj.
Hint Resolve nclose_subseteq' : ndisj.
Hint Resolve (empty_subseteq (A:=positive) (C:=coPset)) : ndisj.
Hint Resolve (union_least (A:=positive) (C:=coPset)) : ndisj.
(* Fallback, loses lots of information but lets other rules make progress. *)
Hint Resolve (subseteq_difference_l (A:=positive) (C:=coPset)) | 100 : ndisj.
Hint Resolve nclose_subseteq' | 100 : ndisj.
(* Rules for goals of the form [_ ## _] *)
(* The base rule that we want to ultimately get down to. *)
Hint Extern 0 (_ ## _) => apply ndot_ne_disjoint; congruence : ndisj.
Hint Resolve ndot_preserve_disjoint_l ndot_preserve_disjoint_r : ndisj.
Hint Resolve ndisj_difference_l : ndisj.
Hint Resolve (disjoint_difference_l (A:=positive) (C:=coPset)) | 100 : ndisj.
(* Fallback, loses lots of information but lets other rules make progress.
Tests show trying [disjoint_difference_l1] first gives better performance. *)
Hint Resolve (disjoint_difference_l1 (A:=positive) (C:=coPset)) | 50 : ndisj.
Hint Resolve (disjoint_difference_l2 (A:=positive) (C:=coPset)) | 100 : ndisj.
Hint Resolve ndot_preserve_disjoint_l ndot_preserve_disjoint_r | 100 : ndisj.
Ltac solve_ndisj :=
repeat match goal with
......
......@@ -662,9 +662,13 @@ Section set.
(** Disjointness *)
Lemma disjoint_intersection X Y : X ## Y X Y ∅.
Proof. set_solver. Qed.
Lemma disjoint_difference_l X Y1 Y2 : Y1 ## X Y1 Y2 ## X.
Lemma disjoint_difference_l1 X1 X2 Y : Y X2 X1 X2 ## Y.
Proof. set_solver. Qed.
Lemma disjoint_difference_r X Y1 Y2 : X ## Y1 X ## Y1 Y2.
Lemma disjoint_difference_l2 X1 X2 Y : X1 ## Y X1 X2 ## Y.
Proof. set_solver. Qed.
Lemma disjoint_difference_r1 X Y1 Y2 : X Y2 X ## Y1 Y2.
Proof. set_solver. Qed.
Lemma disjoint_difference_r2 X Y1 Y2 : X ## Y1 X ## Y1 Y2.
Proof. set_solver. Qed.
Section leibniz.
......
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